Solution:-      Amount of (ce{Fe2O3}) present in the ore =   (frac{normalsize80}{normalsize100}times~10~Kg)                                                                                       […]

Solution:-     Atomic masses of    (Pb= 207~amu), (N= 14~amu), (O=16~amu)                       We will have compound formation, that will contain three elements (Pb), (N) and (O)                        Elements                […]

A redox reaction, short for “reduction-oxidation” reaction, is a type of chemical reaction in which there is a transfer of electrons between two substances. These reactions involve changes in the oxidation states (or oxidation numbers) of the participating atoms or ions.

Solution:- \(L\)\(({t^{2}e^{2t}+2\sin(t)\cos(t)+3})\) \(=\)\(L(t^{2}e^{2t})\) +\(L\)\((2\sin(t)\cos(t))\) +\(L(3)\) ——————————-(\(1)\) \(L(t^{2}e^{2t})\)\(=L(t^{2})\).\(L(e^{2t})\) \(=\frac{2}{s^3}.\frac{1}{S-2}\), ——————————————————–(\(a\)) Since, \(L({t^n})\) \(=\) \(\frac{n!}{S^{n+1}}\) \(\Rightarrow\)\(L(t^{2})\)\(=\) \(\frac{2}{S^{2+1}}\) \(=\) \(\frac{2}{S^{3}}\) Since, \(L(e^{at})\)\(=\)\(\frac{1}{(S-a)}\)\(=\)\(\frac{1}{S-2}\) Now, \(L({2\sin(t)\cos(t)})\) Which can be written as \(=L({\sin2(t)})\) \(L(\sin2t)\)\(=\)\(\frac{2}{S^{2}+2^{2}}\) \(=\)\(\frac{2}{(S^{2}+4)}\) ———————————————————–(\(b\)) Since, Laplace transformation of \(L\)\((\sin\)\(at\)) \(=\)\(\frac{a}{S^{2}+a^{2}}\) now, \(L(3)\)\(=\frac{3}{S}\) ———————————————————-(\(c\)) Since, \(L(1)\)\(=\frac{1}{S}\) Now putting the values of (\(a)\), Now putting the values of (\(a)\), Now putting […]

Multiplication of \((0.0043)(0.821)(298)\) is \(1.0520\), Which could be written as \(1.05\) and by rounding off \(1.1\).

Solution:- (a) (frac{x^{2}}{4} +frac{y^{2}}{9}=1) (a=2) and (b=3) from the above relation by changing the variable taking, (u= rcosTheta) and (v=rsinTheta) Jacobian ((J))(=) (=)(frac{du}{dr}) (frac{du}{dtheta}) (frac{dv}{dr}) (frac{dv}{dtheta}) (=)(cos) (-rsintheta) (sintheta) (rcostheta) (=) (rcos^{2}theta+rsin^{2}theta) (=)(r)((sin^{2}theta+cos^{2}theta)) (J)(=)(r).(1) (J)(=)(r) Limits are, (r=0) to(1) and 0 to (2pi) since radius is (1) Area (=) (ab) (int_{0}^{2pi}int_{0}^{1})(rdrdtheta) (=)(2.3int_{0}^{2pi}[r^{2}]_{0}^{1}) (=)(6int_{0}^{2pi}(1-0)dtheta) (=)(6.[theta]_{0}^{2pi}) (=)(frac{12Pi}{2}) […]

Solution:- \(x^{3}+y^{3}-1=0\) \(x^{3}+y^{3}=1\) now, \(\frac{d}{dx}(x^{3}+y^{3})=\frac{d}{dx}(1)\) \(\frac{d}{dx}(x^{3})\)+ \(\frac{d}{dx}(y^{3})= 0\) \(3x^{2}+3y^{2} \frac{d}{dx}=0\) \(3y^{2}\frac{d}{dx}= – 3x^{2}\) \(\frac{d}{dx}\)\(=\)\(-\)\(\frac{x^{2}}{y^{2}}\)

Solution: To solve this question we can take various approach but here we are taking the unit price approach and compare their price to determine which is the better buy (17) ounce can costs (=) ($) (2.49) therefor, (1) ounce can costs (=)(frac{2.49}{17}) (=) ($)(0.146) per ounce (26) ounce can costs (=) ($2.89) therefore, (1) […]